2x^2+3x-1260=0

Solution for 2x^2+3x-1260=0 equation:

2x^2+3x-1260=0

a = 2; b = 3; c = -1260;
Δ = b2-4ac
Δ = 32-4·2·(-1260)
Δ = 10089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{10089}=\sqrt{9*1121}=\sqrt{9}*\sqrt{1121}=3\sqrt{1121}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-3\sqrt{1121}}{2*2}=\frac{-3-3\sqrt{1121}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+3\sqrt{1121}}{2*2}=\frac{-3+3\sqrt{1121}}{4}
$